.. _indexing:

{{ header }}

***************************
Indexing and selecting data
***************************

The axis labeling information in pandas objects serves many purposes:

* Identifies data (i.e. provides *metadata*) using known indicators,
  important for analysis, visualization, and interactive console display.
* Enables automatic and explicit data alignment.
* Allows intuitive getting and setting of subsets of the data set.

In this section, we will focus on the final point: namely, how to slice, dice,
and generally get and set subsets of pandas objects. The primary focus will be
on Series and DataFrame as they have received more development attention in
this area.

.. note::

   The Python and NumPy indexing operators ``[]`` and attribute operator ``.``
   provide quick and easy access to pandas data structures across a wide range
   of use cases. This makes interactive work intuitive, as there's little new
   to learn if you already know how to deal with Python dictionaries and NumPy
   arrays. However, since the type of the data to be accessed isn't known in
   advance, directly using standard operators has some optimization limits. For
   production code, we recommended that you take advantage of the optimized
   pandas data access methods exposed in this chapter.

See the :ref:`MultiIndex / Advanced Indexing <advanced>` for ``MultiIndex`` and more advanced indexing documentation.

See the :ref:`cookbook<cookbook.selection>` for some advanced strategies.

.. _indexing.choice:

Different choices for indexing
------------------------------

Object selection has had a number of user-requested additions in order to
support more explicit location based indexing. pandas now supports three types
of multi-axis indexing.

* ``.loc`` is primarily label based, but may also be used with a boolean array. ``.loc`` will raise ``KeyError`` when the items are not found. Allowed inputs are:

    * A single label, e.g. ``5`` or ``'a'`` (Note that ``5`` is interpreted as a
      *label* of the index. This use is **not** an integer position along the
      index.).
    * A list or array of labels ``['a', 'b', 'c']``.
    * A slice object with labels ``'a':'f'`` (Note that contrary to usual Python
      slices, **both** the start and the stop are included, when present in the
      index! See :ref:`Slicing with labels <indexing.slicing_with_labels>`
      and :ref:`Endpoints are inclusive <advanced.endpoints_are_inclusive>`.)
    * A boolean array (any ``NA`` values will be treated as ``False``).
    * A ``callable`` function with one argument (the calling Series or DataFrame) and
      that returns valid output for indexing (one of the above).
    * A tuple of row (and column) indices whose elements are one of the
      above inputs.

  See more at :ref:`Selection by Label <indexing.label>`.

* ``.iloc`` is primarily integer position based (from ``0`` to
  ``length-1`` of the axis), but may also be used with a boolean
  array.  ``.iloc`` will raise ``IndexError`` if a requested
  indexer is out-of-bounds, except *slice* indexers which allow
  out-of-bounds indexing.  (this conforms with Python/NumPy *slice*
  semantics).  Allowed inputs are:

    * An integer e.g. ``5``.
    * A list or array of integers ``[4, 3, 0]``.
    * A slice object with ints ``1:7``.
    * A boolean array (any ``NA`` values will be treated as ``False``).
    * A ``callable`` function with one argument (the calling Series or DataFrame) and
      that returns valid output for indexing (one of the above).
    * A tuple of row (and column) indices whose elements are one of the
      above inputs.

  See more at :ref:`Selection by Position <indexing.integer>`,
  :ref:`Advanced Indexing <advanced>` and :ref:`Advanced
  Hierarchical <advanced.advanced_hierarchical>`.

* ``.loc``, ``.iloc``, and also ``[]`` indexing can accept a ``callable`` as indexer. See more at :ref:`Selection By Callable <indexing.callable>`.

  .. note::

     Destructuring tuple keys into row (and column) indexes occurs
     *before* callables are applied, so you cannot return a tuple from
     a callable to index both rows and columns.

Getting values from an object with multi-axes selection uses the following
notation (using ``.loc`` as an example, but the following applies to ``.iloc`` as
well). Any of the axes accessors may be the null slice ``:``. Axes left out of
the specification are assumed to be ``:``, e.g. ``p.loc['a']`` is equivalent to
``p.loc['a', :]``.


.. ipython:: python

   ser = pd.Series(range(5), index=list("abcde"))
   ser.loc[["a", "c", "e"]]

   df = pd.DataFrame(np.arange(25).reshape(5, 5), index=list("abcde"), columns=list("abcde"))
   df.loc[["a", "c", "e"], ["b", "d"]]

.. _indexing.basics:

Basics
------

As mentioned when introducing the data structures in the :ref:`last section
<basics>`, the primary function of indexing with ``[]`` (a.k.a. ``__getitem__``
for those familiar with implementing class behavior in Python) is selecting out
lower-dimensional slices. The following table shows return type values when
indexing pandas objects with ``[]``:

.. csv-table::
    :header: "Object Type", "Selection", "Return Value Type"
    :widths: 30, 30, 60

    Series, ``series[label]``, scalar value
    DataFrame, ``frame[colname]``, ``Series`` corresponding to colname

Here we construct a simple time series data set to use for illustrating the
indexing functionality:

.. ipython:: python

   dates = pd.date_range('1/1/2000', periods=8)
   df = pd.DataFrame(np.random.randn(8, 4),
                     index=dates, columns=['A', 'B', 'C', 'D'])
   df

.. note::

   None of the indexing functionality is time series specific unless
   specifically stated.

Thus, as per above, we have the most basic indexing using ``[]``:

.. ipython:: python

   s = df['A']
   s[dates[5]]

You can pass a list of columns to ``[]`` to select columns in that order.
If a column is not contained in the DataFrame, an exception will be
raised. Multiple columns can also be set in this manner:

.. ipython:: python

   df
   df[['B', 'A']] = df[['A', 'B']]
   df

You may find this useful for applying a transform (in-place) to a subset of the
columns.

.. warning::

   pandas aligns all AXES when setting ``Series`` and ``DataFrame`` from ``.loc``.

   This will **not** modify ``df`` because the column alignment is before value assignment.

   .. ipython:: python

      df[['A', 'B']]
      df.loc[:, ['B', 'A']] = df[['A', 'B']]
      df[['A', 'B']]

   The correct way to swap column values is by using raw values:

   .. ipython:: python

      df.loc[:, ['B', 'A']] = df[['A', 'B']].to_numpy()
      df[['A', 'B']]

   However, pandas does not align AXES when setting ``Series`` and ``DataFrame`` from ``.iloc``
   because ``.iloc`` operates by position.

   This will modify ``df`` because the column alignment is not done before value assignment.

   .. ipython:: python

      df[['A', 'B']]
      df.iloc[:, [1, 0]] = df[['A', 'B']]
      df[['A','B']]


Attribute access
----------------

.. _indexing.columns.multiple:

.. _indexing.df_cols:

.. _indexing.attribute_access:

You may access an index on a ``Series`` or  column on a ``DataFrame`` directly
as an attribute:

.. ipython:: python

   sa = pd.Series([1, 2, 3], index=list('abc'))
   dfa = df.copy()

.. ipython:: python

   sa.b
   dfa.A

.. ipython:: python

   sa.a = 5
   sa
   dfa.A = list(range(len(dfa.index)))  # ok if A already exists
   dfa
   dfa['A'] = list(range(len(dfa.index)))  # use this form to create a new column
   dfa

.. warning::

   - You can use this access only if the index element is a valid Python identifier, e.g. ``s.1`` is not allowed.
     See `here for an explanation of valid identifiers
     <https://docs.python.org/3/reference/lexical_analysis.html#identifiers>`__.

   - The attribute will not be available if it conflicts with an existing method name, e.g. ``s.min`` is not allowed, but ``s['min']`` is possible.

   - Similarly, the attribute will not be available if it conflicts with any of the following list: ``index``,
     ``major_axis``, ``minor_axis``, ``items``.

   - In any of these cases, standard indexing will still work, e.g. ``s['1']``, ``s['min']``, and ``s['index']`` will
     access the corresponding element or column.

If you are using the IPython environment, you may also use tab-completion to
see these accessible attributes.

You can also assign a ``dict`` to a row of a ``DataFrame``:

.. ipython:: python

   x = pd.DataFrame({'x': [1, 2, 3], 'y': [3, 4, 5]})
   x.iloc[1] = {'x': 9, 'y': 99}
   x

You can use attribute access to modify an existing element of a Series or column of a DataFrame, but be careful;
if you try to use attribute access to create a new column, it creates a new attribute rather than a
new column and will this raise a ``UserWarning``:

.. ipython:: python
   :okwarning:

    df_new = pd.DataFrame({'one': [1., 2., 3.]})
    df_new.two = [4, 5, 6]
    df_new


Slicing ranges
--------------

The most robust and consistent way of slicing ranges along arbitrary axes is
described in the :ref:`Selection by Position <indexing.integer>` section
detailing the ``.iloc`` method. For now, we explain the semantics of slicing using the ``[]`` operator.

    .. note::

        When the :class:`Series` has float indices, slicing will select by position.

With Series, the syntax works exactly as with an ndarray, returning a slice of
the values and the corresponding labels:

.. ipython:: python

   s[:5]
   s[::2]
   s[::-1]

Note that setting works as well:

.. ipython:: python

   s2 = s.copy()
   s2[:5] = 0
   s2

With DataFrame, slicing inside of ``[]`` **slices the rows**. This is provided
largely as a convenience since it is such a common operation.

.. ipython:: python

   df[:3]
   df[::-1]

.. _indexing.label:

Selection by label
------------------

.. warning::

   ``.loc`` is strict when you present slicers that are not compatible (or convertible) with the index type. For example
   using integers in a ``DatetimeIndex``. These will raise a ``TypeError``.

   .. ipython:: python
      :okexcept:

      dfl = pd.DataFrame(np.random.randn(5, 4),
                         columns=list('ABCD'),
                         index=pd.date_range('20130101', periods=5))
      dfl
      dfl.loc[2:3]

  String likes in slicing *can* be convertible to the type of the index and lead to natural slicing.

  .. ipython:: python

     dfl.loc['20130102':'20130104']

pandas provides a suite of methods in order to have **purely label based indexing**. This is a strict inclusion based protocol.
Every label asked for must be in the index, or a ``KeyError`` will be raised.
When slicing, both the start bound **AND** the stop bound are *included*, if present in the index.
Integers are valid labels, but they refer to the label **and not the position**.

The ``.loc`` attribute is the primary access method. The following are valid inputs:

* A single label, e.g. ``5`` or ``'a'`` (Note that ``5`` is interpreted as a *label* of the index. This use is **not** an integer position along the index.).
* A list or array of labels ``['a', 'b', 'c']``.
* A slice object with labels ``'a':'f'``. Note that contrary to usual Python
  slices, **both** the start and the stop are included, when present in the
  index! See :ref:`Slicing with labels <indexing.slicing_with_labels>`.
* A boolean array.
* A ``callable``, see :ref:`Selection By Callable <indexing.callable>`.

.. ipython:: python

   s1 = pd.Series(np.random.randn(6), index=list('abcdef'))
   s1
   s1.loc['c':]
   s1.loc['b']

Note that setting works as well:

.. ipython:: python

   s1.loc['c':] = 0
   s1

With a DataFrame:

.. ipython:: python

   df1 = pd.DataFrame(np.random.randn(6, 4),
                      index=list('abcdef'),
                      columns=list('ABCD'))
   df1
   df1.loc[['a', 'b', 'd'], :]

Accessing via label slices:

.. ipython:: python

   df1.loc['d':, 'A':'C']

For getting a cross section using a label (equivalent to ``df.xs('a')``):

.. ipython:: python

   df1.loc['a']

For getting values with a boolean array:

.. ipython:: python

   df1.loc['a'] > 0
   df1.loc[:, df1.loc['a'] > 0]

NA values in a boolean array propagate as ``False``:

.. ipython:: python

   mask = pd.array([True, False, True, False, pd.NA, False], dtype="boolean")
   mask
   df1[mask]

For getting a value explicitly:

.. ipython:: python

   # this is also equivalent to ``df1.at['a','A']``
   df1.loc['a', 'A']

.. _indexing.slicing_with_labels:

Slicing with labels
~~~~~~~~~~~~~~~~~~~

When using ``.loc`` with slices, if both the start and the stop labels are
present in the index, then elements *located* between the two (including them)
are returned:

.. ipython:: python

   s = pd.Series(list('abcde'), index=[0, 3, 2, 5, 4])
   s.loc[3:5]

If the index is sorted, and can be compared against start and stop labels,
then slicing will still work as expected, by selecting labels which *rank*
between the two:

.. ipython:: python

   s.sort_index()
   s.sort_index().loc[1:6]

However, if at least one of the two is absent *and* the index is not sorted, an
error will be raised (since doing otherwise would be computationally expensive,
as well as potentially ambiguous for mixed type indexes). For instance, in the
above example, ``s.loc[1:6]`` would raise ``KeyError``.

For the rationale behind this behavior, see
:ref:`Endpoints are inclusive <advanced.endpoints_are_inclusive>`.

.. ipython:: python

   s = pd.Series(list('abcdef'), index=[0, 3, 2, 5, 4, 2])
   s.loc[3:5]

Also, if the index has duplicate labels *and* either the start or the stop label is duplicated,
an error will be raised. For instance, in the above example, ``s.loc[2:5]`` would raise a ``KeyError``.

For more information about duplicate labels, see
:ref:`Duplicate Labels <duplicates>`.

When using a slice with a step, such as ``.loc[start:stop:step]``, note that
*start* and *stop* are interpreted as **labels**, while *step* is applied over
the **positional index** within that label range. This means a stepped slice
will behave differently than using the labels ``range(start, stop, step)`` when
the index is not contiguous integers.

For example, in a ``Series`` with a non-contiguous integer index:

.. ipython:: python

    s = pd.Series(range(10), index=[0, 5, 10, 15, 20, 25, 30, 35, 40, 45])
    s.loc[10:50:5]              # (10), then skip 5 positions → 35 only
    s.loc[[10, 15, 20, 25]]     # explicit label selection

The first applies *step* across **positional locations** between the start/stop
labels. The second selects each label directly.

Similarly, with a string-based index, the behavior is identical:

.. ipython:: python

    s = pd.Series(range(10), index=['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j'])
    s.loc['b':'i':2]            # Start at 'b' (position 1), stop at 'i' (position 8), step 2 positions → 'b', 'd', 'f', 'h'
    s.loc[['b', 'd', 'f', 'h']] # explicit label selection

In both cases, *start* and *stop* determine the label boundaries (inclusive),
while *step* skips positions within that range, regardless of the index type.



.. _indexing.integer:

Selection by position
---------------------

pandas provides a suite of methods in order to get **purely integer based indexing**. The semantics follow closely Python and NumPy slicing. These are ``0-based`` indexing. When slicing, the start bound is *included*, while the upper bound is *excluded*. Trying to use a non-integer, even a **valid** label will raise an ``IndexError``.

The ``.iloc`` attribute is the primary access method. The following are valid inputs:

* An integer e.g. ``5``.
* A list or array of integers ``[4, 3, 0]``.
* A slice object with ints ``1:7``.
* A boolean array.
* A ``callable``, see :ref:`Selection By Callable <indexing.callable>`.
* A tuple of row (and column) indexes, whose elements are one of the
  above types.

.. ipython:: python

   s1 = pd.Series(np.random.randn(5), index=list(range(0, 10, 2)))
   s1
   s1.iloc[:3]
   s1.iloc[3]

Note that setting works as well:

.. ipython:: python

   s1.iloc[:3] = 0
   s1

With a DataFrame:

.. ipython:: python

   df1 = pd.DataFrame(np.random.randn(6, 4),
                      index=list(range(0, 12, 2)),
                      columns=list(range(0, 8, 2)))
   df1

Select via integer slicing:

.. ipython:: python

   df1.iloc[:3]
   df1.iloc[1:5, 2:4]

Select via integer list:

.. ipython:: python

   df1.iloc[[1, 3, 5], [1, 3]]

.. ipython:: python

   df1.iloc[1:3, :]

.. ipython:: python

   df1.iloc[:, 1:3]

.. ipython:: python

   # this is also equivalent to ``df1.iat[1,1]``
   df1.iloc[1, 1]

For getting a cross section using an integer position (equiv to ``df.xs(1)``):

.. ipython:: python

   df1.iloc[1]

Out of range slice indexes are handled gracefully just as in Python/NumPy.

.. ipython:: python

    # these are allowed in Python/NumPy.
    x = list('abcdef')
    x
    x[4:10]
    x[8:10]
    s = pd.Series(x)
    s
    s.iloc[4:10]
    s.iloc[8:10]

Note that using slices that go out of bounds can result in
an empty axis (e.g. an empty DataFrame being returned).

.. ipython:: python

   dfl = pd.DataFrame(np.random.randn(5, 2), columns=list('AB'))
   dfl
   dfl.iloc[:, 2:3]
   dfl.iloc[:, 1:3]
   dfl.iloc[4:6]

A single indexer that is out of bounds will raise an ``IndexError``.
A list of indexers where any element is out of bounds will raise an
``IndexError``.

.. ipython:: python
   :okexcept:

   dfl.iloc[[4, 5, 6]]

.. ipython:: python
   :okexcept:

   dfl.iloc[:, 4]

.. _indexing.callable:

Selection by callable
---------------------

``.loc``, ``.iloc``, and also ``[]`` indexing can accept a ``callable`` as indexer.
The ``callable`` must be a function with one argument (the calling Series or DataFrame) that returns valid output for indexing.

.. note::

   For ``.iloc`` indexing, returning a tuple from the callable is
   not supported, since tuple destructuring for row and column indexes
   occurs *before* applying callables.

.. ipython:: python

   df1 = pd.DataFrame(np.random.randn(6, 4),
                      index=list('abcdef'),
                      columns=list('ABCD'))
   df1

   df1.loc[lambda df: df['A'] > 0, :]
   df1.loc[:, lambda df: ['A', 'B']]

   df1.iloc[:, lambda df: [0, 1]]

   df1[lambda df: df.columns[0]]


You can use callable indexing in ``Series``.

.. ipython:: python

   df1['A'].loc[lambda s: s > 0]

Using these methods / indexers, you can chain data selection operations
without using a temporary variable.

.. ipython:: python

   bb = pd.read_csv('data/baseball.csv', index_col='id')
   (bb.groupby(['year', 'team']).sum(numeric_only=True)
      .loc[lambda df: df['r'] > 100])


.. _combining_positional_and_label_based_indexing:

Combining positional and label-based indexing
---------------------------------------------

If you wish to get the 0th and the 2nd elements from the index in the 'A' column, you can do:

.. ipython:: python

  dfd = pd.DataFrame({'A': [1, 2, 3],
                      'B': [4, 5, 6]},
                     index=list('abc'))
  dfd
  dfd.loc[dfd.index[[0, 2]], 'A']

This can also be expressed using ``.iloc``, by explicitly getting locations on the indexers, and using
*positional* indexing to select things.

.. ipython:: python

  dfd.iloc[[0, 2], dfd.columns.get_loc('A')]

For getting *multiple* indexers, using ``.get_indexer``:

.. ipython:: python

  dfd.iloc[[0, 2], dfd.columns.get_indexer(['A', 'B'])]


Reindexing
~~~~~~~~~~

The idiomatic way to achieve selecting potentially not-found elements is via ``.reindex()``. See also the section on :ref:`reindexing <basics.reindexing>`.

.. ipython:: python

  s = pd.Series([1, 2, 3])
  s.reindex([1, 2, 3])

Alternatively, if you want to select only *valid* keys, the following is idiomatic and efficient; it is guaranteed to preserve the dtype of the selection.

.. ipython:: python

   labels = [1, 2, 3]
   s.loc[s.index.intersection(labels)]

Having a duplicated index will raise for a ``.reindex()``:

.. ipython:: python
   :okexcept:

   s = pd.Series(np.arange(4), index=['a', 'a', 'b', 'c'])
   labels = ['c', 'd']
   s.reindex(labels)

Generally, you can intersect the desired labels with the current
axis, and then reindex.

.. ipython:: python

   s.loc[s.index.intersection(labels)].reindex(labels)

However, this would *still* raise if your resulting index is duplicated.

.. ipython:: python
   :okexcept:

   labels = ['a', 'd']
   s.loc[s.index.intersection(labels)].reindex(labels)


.. _indexing.basics.partial_setting:

Selecting random samples
------------------------

A random selection of rows or columns from a Series or DataFrame with the :meth:`~DataFrame.sample` method. The method will sample rows by default, and accepts a specific number of rows/columns to return, or a fraction of rows.

.. ipython:: python

    s = pd.Series([0, 1, 2, 3, 4, 5])

    # When no arguments are passed, returns 1 row.
    s.sample()

    # One may specify either a number of rows:
    s.sample(n=3)

    # Or a fraction of the rows:
    s.sample(frac=0.5)

By default, ``sample`` will return each row at most once, but one can also sample with replacement
using the ``replace`` option:

.. ipython:: python

    s = pd.Series([0, 1, 2, 3, 4, 5])

    # Without replacement (default):
    s.sample(n=6, replace=False)

    # With replacement:
    s.sample(n=6, replace=True)


By default, each row has an equal probability of being selected, but if you want rows
to have different probabilities, you can pass the ``sample`` function sampling weights as
``weights``. These weights can be a list, a NumPy array, or a Series, but they must be of the same length as the object you are sampling. Missing values will be treated as a weight of zero, and inf values are not allowed. If weights do not sum to 1, they will be re-normalized by dividing all weights by the sum of the weights. For example:

.. ipython:: python

    s = pd.Series([0, 1, 2, 3, 4, 5])
    example_weights = [0, 0, 0.2, 0.2, 0.2, 0.4]
    s.sample(n=2, weights=example_weights)

    # Weights will be re-normalized automatically
    example_weights2 = [0.5, 0, 0, 0, 0, 0]
    s.sample(n=1, weights=example_weights2)

When applied to a DataFrame, you can use a column of the DataFrame as sampling weights
(provided you are sampling rows and not columns) by simply passing the name of the column
as a string.

.. ipython:: python

    df2 = pd.DataFrame({'col1': [9, 8, 7, 6],
                        'weight_column': [0.5, 0.4, 0.1, 0]})
    df2.sample(n=2, weights='weight_column')

``sample`` also allows users to sample columns instead of rows using the ``axis`` argument.

.. ipython:: python

    df3 = pd.DataFrame({'col1': [1, 2, 3], 'col2': [2, 3, 4]})
    df3.sample(n=1, axis=1)

Finally, one can also set a seed for ``sample``'s random number generator using the ``random_state`` argument, which will accept either an integer (as a seed) or a NumPy RandomState object.

.. ipython:: python

    df4 = pd.DataFrame({'col1': [1, 2, 3], 'col2': [2, 3, 4]})

    # With a given seed, the sample will always draw the same rows.
    df4.sample(n=2, random_state=2)
    df4.sample(n=2, random_state=2)



Setting with enlargement
------------------------

The ``.loc/[]`` operations can perform enlargement when setting a non-existent key for that axis.

In the ``Series`` case this is effectively an appending operation.

.. ipython:: python

   se = pd.Series([1, 2, 3])
   se
   se[5] = 5.
   se

A ``DataFrame`` can be enlarged on either axis via ``.loc``.

.. ipython:: python

   dfi = pd.DataFrame(np.arange(6).reshape(3, 2),
                      columns=['A', 'B'])
   dfi
   dfi.loc[:, 'C'] = dfi.loc[:, 'A']
   dfi

This is like an ``append`` operation on the ``DataFrame``.

.. ipython:: python

   dfi.loc[3] = 5
   dfi

.. _indexing.basics.get_value:

Fast scalar value getting and setting
-------------------------------------

Since indexing with ``[]`` must handle a lot of cases (single-label access,
slicing, boolean indexing, etc.), it has a bit of overhead in order to figure
out what you're asking for. If you only want to access a scalar value, the
fastest way is to use the ``at`` and ``iat`` methods, which are implemented on
all of the data structures.

Similarly to ``loc``, ``at`` provides **label** based scalar lookups, while, ``iat`` provides **integer** based lookups analogously to ``iloc``

.. ipython:: python

   s.iat[5]
   df.at[dates[5], 'A']
   df.iat[3, 0]

You can also set using these same indexers.

.. ipython:: python

   df.at[dates[5], 'E'] = 7
   df.iat[3, 0] = 7

``at`` may enlarge the object in-place as above if the indexer is missing.

.. ipython:: python

   df.at[dates[-1] + pd.Timedelta('1 day'), 0] = 7
   df

Boolean indexing
----------------

.. _indexing.boolean:

Another common operation is the use of boolean vectors to filter the data.
The operators are: ``|`` for ``or``, ``&`` for ``and``, and ``~`` for ``not``.
These **must** be grouped by using parentheses, since by default Python will
evaluate an expression such as ``df['A'] > 2 & df['B'] < 3`` as
``df['A'] > (2 & df['B']) < 3``, while the desired evaluation order is
``(df['A'] > 2) & (df['B'] < 3)``.

Using a boolean vector to index a Series works exactly as in a NumPy ndarray:

.. ipython:: python

   s = pd.Series(range(-3, 4))
   s
   s[s > 0]
   s[(s < -1) | (s > 0.5)]
   s[~(s < 0)]

You may select rows from a DataFrame using a boolean vector the same length as
the DataFrame's index (for example, something derived from one of the columns
of the DataFrame):

.. ipython:: python

   df[df['A'] > 0]

List comprehensions and the ``map`` method of Series can also be used to produce
more complex criteria:

.. ipython:: python

   df2 = pd.DataFrame({'a': ['one', 'one', 'two', 'three', 'two', 'one', 'six'],
                       'b': ['x', 'y', 'y', 'x', 'y', 'x', 'x'],
                       'c': np.random.randn(7)})

   # only want 'two' or 'three'
   criterion = df2['a'].map(lambda x: x.startswith('t'))

   df2[criterion]

   # equivalent but slower
   df2[[x.startswith('t') for x in df2['a']]]

   # Multiple criteria
   df2[criterion & (df2['b'] == 'x')]

With the choice methods :ref:`Selection by Label <indexing.label>`, :ref:`Selection by Position <indexing.integer>`,
and :ref:`Advanced Indexing <advanced>` you may select along more than one axis using boolean vectors combined with other indexing expressions.

.. ipython:: python

   df2.loc[criterion & (df2['b'] == 'x'), 'b':'c']

.. warning::

   While ``loc`` supports two kinds of boolean indexing, ``iloc`` only supports indexing with a
   boolean array. If the indexer is a boolean ``Series``, an error will be raised. For instance,
   in the following example, ``df.iloc[s.values, 1]`` is ok. The boolean indexer is an array.
   But ``df.iloc[s, 1]`` would raise ``ValueError``.

   .. ipython:: python

      df = pd.DataFrame([[1, 2], [3, 4], [5, 6]],
                        index=list('abc'),
                        columns=['A', 'B'])
      s = (df['A'] > 2)
      s

      df.loc[s, 'B']

      df.iloc[s.values, 1]

.. _indexing.basics.indexing_isin:

Indexing with isin
------------------

Consider the :meth:`~Series.isin` method of ``Series``, which returns a boolean
vector that is true wherever the ``Series`` elements exist in the passed list.
This allows you to select rows where one or more columns have values you want:

.. ipython:: python

   s = pd.Series(np.arange(5), index=np.arange(5)[::-1], dtype='int64')
   s
   s.isin([2, 4, 6])
   s[s.isin([2, 4, 6])]

The same method is available for ``Index`` objects and is useful for the cases
when you don't know which of the sought labels are in fact present:

.. ipython:: python

   s[s.index.isin([2, 4, 6])]

   # compare it to the following
   s.reindex([2, 4, 6])

In addition to that, ``MultiIndex`` allows selecting a separate level to use
in the membership check:

.. ipython:: python

   s_mi = pd.Series(np.arange(6),
                    index=pd.MultiIndex.from_product([[0, 1], ['a', 'b', 'c']]))
   s_mi
   s_mi.iloc[s_mi.index.isin([(1, 'a'), (2, 'b'), (0, 'c')])]
   s_mi.iloc[s_mi.index.isin(['a', 'c', 'e'], level=1)]

DataFrame also has an :meth:`~DataFrame.isin` method.  When calling ``isin``, pass a set of
values as either an array or dict.  If values is an array, ``isin`` returns
a DataFrame of booleans that is the same shape as the original DataFrame, with True
wherever the element is in the sequence of values.

.. ipython:: python

   df = pd.DataFrame({'vals': [1, 2, 3, 4], 'ids': ['a', 'b', 'f', 'n'],
                      'ids2': ['a', 'n', 'c', 'n']})

   values = ['a', 'b', 1, 3]

   df.isin(values)

Oftentimes you'll want to match certain values with certain columns.
Just make values a ``dict`` where the key is the column, and the value is
a list of items you want to check for.

.. ipython:: python

   values = {'ids': ['a', 'b'], 'vals': [1, 3]}

   df.isin(values)

To return the DataFrame of booleans where the values are *not* in the original DataFrame,
use the ``~`` operator:

.. ipython:: python

   values = {'ids': ['a', 'b'], 'vals': [1, 3]}

   ~df.isin(values)

Combine DataFrame's ``isin`` with the ``any()`` and ``all()`` methods to
quickly select subsets of your data that meet a given criteria.
To select a row where each column meets its own criterion:

.. ipython:: python

  values = {'ids': ['a', 'b'], 'ids2': ['a', 'c'], 'vals': [1, 3]}

  row_mask = df.isin(values).all(axis=1)

  df[row_mask]

.. _indexing.where_mask:

The :meth:`~pandas.DataFrame.where` Method and Masking
------------------------------------------------------

Selecting values from a Series with a boolean vector generally returns a
subset of the data. To guarantee that selection output has the same shape as
the original data, you can use the ``where`` method in ``Series`` and ``DataFrame``.

To return only the selected rows:

.. ipython:: python

   s[s > 0]

To return a Series of the same shape as the original:

.. ipython:: python

   s.where(s > 0)

Selecting values from a DataFrame with a boolean criterion now also preserves
input data shape. ``where`` is used under the hood as the implementation.
The code below is equivalent to ``df.where(df < 0)``.

.. ipython:: python

   dates = pd.date_range('1/1/2000', periods=8)
   df = pd.DataFrame(np.random.randn(8, 4),
                     index=dates, columns=['A', 'B', 'C', 'D'])
   df[df < 0]

In addition, ``where`` takes an optional ``other`` argument for replacement of
values where the condition is False, in the returned copy.

.. ipython:: python

   df.where(df < 0, -df)

You may wish to set values based on some boolean criteria.
This can be done intuitively like so:

.. ipython:: python

   s2 = s.copy()
   s2[s2 < 0] = 0
   s2

   df2 = df.copy()
   df2[df2 < 0] = 0
   df2

``where`` returns a modified copy of the data.

.. note::

   The signature for :func:`DataFrame.where` differs from :func:`numpy.where`.
   Roughly ``df1.where(m, df2)`` is equivalent to ``np.where(m, df1, df2)``.

   .. ipython:: python

      df.where(df < 0, -df) == np.where(df < 0, df, -df)

**Alignment**

Furthermore, ``where`` aligns the input boolean condition (ndarray or DataFrame),
such that partial selection with setting is possible. This is analogous to
partial setting via ``.loc`` (but on the contents rather than the axis labels).

.. ipython:: python

   df2 = df.copy()
   df2[df2[1:4] > 0] = 3
   df2

Where can also accept ``axis`` and ``level`` parameters to align the input when
performing the ``where``.

.. ipython:: python

   df2 = df.copy()
   df2.where(df2 > 0, df2['A'], axis='index')

This is equivalent to (but faster than) the following.

.. ipython:: python

   df2 = df.copy()
   df.apply(lambda x, y: x.where(x > 0, y), y=df['A'])

``where`` can accept a callable as condition and ``other`` arguments. The function must
be with one argument (the calling Series or DataFrame) and that returns valid output
as condition and ``other`` argument.

.. ipython:: python

   df3 = pd.DataFrame({'A': [1, 2, 3],
                       'B': [4, 5, 6],
                       'C': [7, 8, 9]})
   df3.where(lambda x: x > 4, lambda x: x + 10)

Mask
~~~~

:meth:`~pandas.DataFrame.mask` is the inverse boolean operation of ``where``.

.. ipython:: python

   s.mask(s >= 0)
   df.mask(df >= 0)

.. _indexing.np_where:

Setting with enlargement conditionally using :func:`numpy`
----------------------------------------------------------

An alternative to :meth:`~pandas.DataFrame.where` is to use :func:`numpy.where`.
Combined with setting a new column, you can use it to enlarge a DataFrame where the
values are determined conditionally.

Consider you have two choices to choose from in the following DataFrame. And you want to
set a new column color to 'green' when the second column has 'Z'.  You can do the
following:

.. ipython:: python

   df = pd.DataFrame({'col1': list('ABBC'), 'col2': list('ZZXY')})
   df['color'] = np.where(df['col2'] == 'Z', 'green', 'red')
   df

If you have multiple conditions, you can use :func:`numpy.select` to achieve that.  Say
corresponding to three conditions there are three choice of colors, with a fourth color
as a fallback, you can do the following.

.. ipython:: python

   conditions = [
       (df['col2'] == 'Z') & (df['col1'] == 'A'),
       (df['col2'] == 'Z') & (df['col1'] == 'B'),
       (df['col1'] == 'B')
   ]
   choices = ['yellow', 'blue', 'purple']
   df['color'] = np.select(conditions, choices, default='black')
   df

.. _indexing.query:

The :meth:`~pandas.DataFrame.query` Method
------------------------------------------

:class:`~pandas.DataFrame` objects have a :meth:`~pandas.DataFrame.query`
method that allows selection using an expression.

You can get the value of the frame where column ``b`` has values
between the values of columns ``a`` and ``c``. For example:

.. ipython:: python

   n = 10
   df = pd.DataFrame(np.random.rand(n, 3), columns=list('abc'))
   df

   # pure python
   df[(df['a'] < df['b']) & (df['b'] < df['c'])]

   # query
   df.query('(a < b) & (b < c)')

Do the same thing but fall back on a named index if there is no column
with the name ``a``.

.. ipython:: python

   df = pd.DataFrame(np.random.randint(n / 2, size=(n, 2)), columns=list('bc'))
   df.index.name = 'a'
   df
   df.query('a < b and b < c')

If instead you don't want to or cannot name your index, you can use the name
``index`` in your query expression:

.. ipython:: python

   df = pd.DataFrame(np.random.randint(n, size=(n, 2)), columns=list('bc'))
   df
   df.query('index < b < c')

.. note::

   If the name of your index overlaps with a column name, the column name is
   given precedence. For example,

   .. ipython:: python

      df = pd.DataFrame({'a': np.random.randint(5, size=5)})
      df.index.name = 'a'
      df.query('a > 2')  # uses the column 'a', not the index

   You can still use the index in a query expression by using the special
   identifier 'index':

   .. ipython:: python

      df.query('index > 2')

   If for some reason you have a column named ``index``, then you can refer to
   the index as ``ilevel_0`` as well, but at this point you should consider
   renaming your columns to something less ambiguous.

:class:`~pandas.MultiIndex` :meth:`~pandas.DataFrame.query` Syntax
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

You can also use the levels of a ``DataFrame`` with a
:class:`~pandas.MultiIndex` as if they were columns in the frame:

.. ipython:: python

   n = 10
   colors = np.random.choice(['red', 'green'], size=n)
   foods = np.random.choice(['eggs', 'ham'], size=n)
   colors
   foods

   index = pd.MultiIndex.from_arrays([colors, foods], names=['color', 'food'])
   df = pd.DataFrame(np.random.randn(n, 2), index=index)
   df
   df.query('color == "red"')

If the levels of the ``MultiIndex`` are unnamed, you can refer to them using
special names:

.. ipython:: python

   df.index.names = [None, None]
   df
   df.query('ilevel_0 == "red"')


The convention is ``ilevel_0``, which means "index level 0" for the 0th level
of the ``index``.


:meth:`~pandas.DataFrame.query` Use Cases
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

A use case for :meth:`~pandas.DataFrame.query` is when you have a collection of
:class:`~pandas.DataFrame` objects that have a subset of column names (or index
levels/names) in common. You can pass the same query to both frames *without*
having to specify which frame you're interested in querying

.. ipython:: python

   df = pd.DataFrame(np.random.rand(n, 3), columns=list('abc'))
   df
   df2 = pd.DataFrame(np.random.rand(n + 2, 3), columns=df.columns)
   df2
   expr = '0.0 <= a <= c <= 0.5'
   map(lambda frame: frame.query(expr), [df, df2])

:meth:`~pandas.DataFrame.query` Python versus pandas Syntax Comparison
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Full numpy-like syntax:

.. ipython:: python

   df = pd.DataFrame(np.random.randint(n, size=(n, 3)), columns=list('abc'))
   df
   df.query('(a < b) & (b < c)')
   df[(df['a'] < df['b']) & (df['b'] < df['c'])]

Slightly nicer by removing the parentheses (comparison operators bind tighter
than ``&`` and ``|``):

.. ipython:: python

   df.query('a < b & b < c')

Use English instead of symbols:

.. ipython:: python

   df.query('a < b and b < c')

Pretty close to how you might write it on paper:

.. ipython:: python

   df.query('a < b < c')

The ``in`` and ``not in`` operators
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

:meth:`~pandas.DataFrame.query` also supports special use of Python's ``in`` and
``not in`` comparison operators, providing a succinct syntax for calling the
``isin`` method of a ``Series`` or ``DataFrame``.

.. ipython:: python

   # get all rows where columns "a" and "b" have overlapping values
   df = pd.DataFrame({'a': list('aabbccddeeff'), 'b': list('aaaabbbbcccc'),
                      'c': np.random.randint(5, size=12),
                      'd': np.random.randint(9, size=12)})
   df
   df.query('a in b')

   # How you'd do it in pure Python
   df[df['a'].isin(df['b'])]

   df.query('a not in b')

   # pure Python
   df[~df['a'].isin(df['b'])]


You can combine this with other expressions for very succinct queries:


.. ipython:: python

   # rows where cols a and b have overlapping values
   # and col c's values are less than col d's
   df.query('a in b and c < d')

   # pure Python
   df[df['b'].isin(df['a']) & (df['c'] < df['d'])]


.. note::

   Note that ``in`` and ``not in`` are evaluated in Python, since ``numexpr``
   has no equivalent of this operation. However, **only the** ``in``/``not in``
   **expression itself** is evaluated in vanilla Python. For example, in the
   expression

   .. code-block:: python

      df.query('a in b + c + d')

   ``(b + c + d)`` is evaluated by ``numexpr`` and *then* the ``in``
   operation is evaluated in plain Python. In general, any operations that can
   be evaluated using ``numexpr`` will be.

Special use of the ``==`` operator with ``list`` objects
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Comparing a ``list`` of values to a column using ``==``/``!=`` works similarly
to ``in``/``not in``.

.. ipython:: python

   df.query('b == ["a", "b", "c"]')

   # pure Python
   df[df['b'].isin(["a", "b", "c"])]

   df.query('c == [1, 2]')

   df.query('c != [1, 2]')

   # using in/not in
   df.query('[1, 2] in c')

   df.query('[1, 2] not in c')

   # pure Python
   df[df['c'].isin([1, 2])]


Boolean operators
~~~~~~~~~~~~~~~~~

You can negate boolean expressions with the word ``not`` or the ``~`` operator.

.. ipython:: python

   df = pd.DataFrame(np.random.rand(n, 3), columns=list('abc'))
   df['bools'] = np.random.rand(len(df)) > 0.5
   df.query('~bools')
   df.query('not bools')
   df.query('not bools') == df[~df['bools']]

Of course, expressions can be arbitrarily complex too:

.. ipython:: python

   # short query syntax
   shorter = df.query('a < b < c and (not bools) or bools > 2')

   # equivalent in pure Python
   longer = df[(df['a'] < df['b'])
               & (df['b'] < df['c'])
               & (~df['bools'])
               | (df['bools'] > 2)]

   shorter
   longer

   shorter == longer


Performance of :meth:`~pandas.DataFrame.query`
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

``DataFrame.query()`` using ``numexpr`` is slightly faster than Python for
large frames.

..
    The eval-perf.png figure below was generated with /doc/scripts/eval_performance.py

.. image:: ../_static/query-perf.png



You will only see the performance benefits of using the ``numexpr`` engine
with ``DataFrame.query()`` if your frame has more than approximately 100,000
rows.



This plot was created using a ``DataFrame`` with 3 columns each containing
floating point values generated using ``numpy.random.randn()``.

.. ipython:: python

   df = pd.DataFrame(np.random.randn(8, 4),
                     index=dates, columns=['A', 'B', 'C', 'D'])
   df2 = df.copy()


Duplicate data
--------------

.. _indexing.duplicate:

If you want to identify and remove duplicate rows in a DataFrame,  there are
two methods that will help: ``duplicated`` and ``drop_duplicates``. Each
takes as an argument the columns to use to identify duplicated rows.

* ``duplicated`` returns a boolean vector whose length is the number of rows, and which indicates whether a row is duplicated.
* ``drop_duplicates`` removes duplicate rows.

By default, the first observed row of a duplicate set is considered unique, but
each method has a ``keep`` parameter to specify targets to be kept.

* ``keep='first'`` (default): mark / drop duplicates except for the first occurrence.
* ``keep='last'``: mark / drop duplicates except for the last occurrence.
* ``keep=False``: mark  / drop all duplicates.

.. ipython:: python

   df2 = pd.DataFrame({'a': ['one', 'one', 'two', 'two', 'two', 'three', 'four'],
                       'b': ['x', 'y', 'x', 'y', 'x', 'x', 'x'],
                       'c': np.random.randn(7)})
   df2
   df2.duplicated('a')
   df2.duplicated('a', keep='last')
   df2.duplicated('a', keep=False)
   df2.drop_duplicates('a')
   df2.drop_duplicates('a', keep='last')
   df2.drop_duplicates('a', keep=False)

Also, you can pass a list of columns to identify duplications.

.. ipython:: python

   df2.duplicated(['a', 'b'])
   df2.drop_duplicates(['a', 'b'])

To drop duplicates by index value, use ``Index.duplicated`` then perform slicing.
The same set of options are available for the ``keep`` parameter.

.. ipython:: python

   df3 = pd.DataFrame({'a': np.arange(6),
                       'b': np.random.randn(6)},
                      index=['a', 'a', 'b', 'c', 'b', 'a'])
   df3
   df3.index.duplicated()
   df3[~df3.index.duplicated()]
   df3[~df3.index.duplicated(keep='last')]
   df3[~df3.index.duplicated(keep=False)]

.. _indexing.dictionarylike:

Dictionary-like :meth:`~pandas.DataFrame.get` method
----------------------------------------------------

Each of Series or DataFrame have a ``get`` method which can return a
default value.

.. ipython:: python

   s = pd.Series([1, 2, 3], index=['a', 'b', 'c'])
   s.get('a')  # equivalent to s['a']
   s.get('x', default=-1)

.. _indexing.lookup:

Looking up values by index/column labels
----------------------------------------

Sometimes you want to extract a set of values given a sequence of row labels
and column labels, this can be achieved by ``pandas.factorize``  and NumPy indexing.

For heterogeneous column types, we subset columns to avoid unnecessary NumPy conversions:

.. code-block:: python

   def pd_lookup_het(df, row_labels, col_labels):
      rows = df.index.get_indexer(row_labels)
      cols = df.columns.get_indexer(col_labels)
      sub = df.take(np.unique(cols), axis=1)
      sub = sub.take(np.unique(rows), axis=0)
      rows = sub.index.get_indexer(row_labels)
      values = sub.melt()["value"]
      cols = sub.columns.get_indexer(col_labels)
      flat_index = rows + cols * len(sub)
      result = values[flat_index]
      return result

For homogeneous column types, it is fastest to skip column subsetting and go directly to NumPy:

.. code-block:: python

   def pd_lookup_hom(df, row_labels, col_labels):
       rows = df.index.get_indexer(row_labels)
       df = df.loc[:, sorted(set(col_labels))]
       cols = df.columns.get_indexer(col_labels)
       result = df.to_numpy()[rows, cols]
       return result

Formerly this could be achieved with the dedicated ``DataFrame.lookup`` method
which was deprecated in version 1.2.0 and removed in version 2.0.0.

.. _indexing.class:

Index objects
-------------

The pandas :class:`~pandas.Index` class and its subclasses can be viewed as
implementing an *ordered multiset*. Duplicates are allowed.

:class:`~pandas.Index` also provides the infrastructure necessary for
lookups, data alignment, and reindexing. The easiest way to create an
:class:`~pandas.Index` directly is to pass a ``list`` or other sequence to
:class:`~pandas.Index`:

.. ipython:: python

   index = pd.Index(['e', 'd', 'a', 'b'])
   index
   'd' in index

or using numbers:

.. ipython:: python

   index = pd.Index([1, 5, 12])
   index
   5 in index

If no dtype is given, ``Index`` tries to infer the dtype from the data.
It is also possible to give an explicit dtype when instantiating an :class:`Index`:

.. ipython:: python

   index = pd.Index(['e', 'd', 'a', 'b'], dtype="string")
   index
   index = pd.Index([1, 5, 12], dtype="int8")
   index
   index = pd.Index([1, 5, 12], dtype="float32")
   index

You can also pass a ``name`` to be stored in the index:

.. ipython:: python

   index = pd.Index(['e', 'd', 'a', 'b'], name='something')
   index.name

The name, if set, will be shown in the console display:

.. ipython:: python

   index = pd.Index(list(range(5)), name='rows')
   columns = pd.Index(['A', 'B', 'C'], name='cols')
   df = pd.DataFrame(np.random.randn(5, 3), index=index, columns=columns)
   df
   df['A']

.. _indexing.set_metadata:

Setting metadata
~~~~~~~~~~~~~~~~

Indexes are "mostly immutable", but it is possible to set and change their
``name`` attribute. You can use the ``rename``, ``set_names`` to set these attributes
directly, and they default to returning a copy.

See :ref:`Advanced Indexing <advanced>` for usage of MultiIndexes.

.. ipython:: python

  ind = pd.Index([1, 2, 3])
  ind.rename("apple")
  ind
  ind = ind.set_names(["apple"])
  ind.name = "bob"
  ind

``set_names``, ``set_levels``, and ``set_codes`` also take an optional
``level`` argument

.. ipython:: python

  index = pd.MultiIndex.from_product([range(3), ['one', 'two']], names=['first', 'second'])
  index
  index.levels[1]
  index.set_levels(["a", "b"], level=1)

.. _indexing.set_ops:

Set operations on Index objects
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The two main operations are ``union`` and ``intersection``.
Difference is provided via the ``.difference()`` method.

.. ipython:: python

   a = pd.Index(['c', 'b', 'a'])
   b = pd.Index(['c', 'e', 'd'])
   a.difference(b)

Also available is the ``symmetric_difference`` operation, which returns elements
that appear in either ``idx1`` or ``idx2``, but not in both. This is
equivalent to the Index created by ``idx1.difference(idx2).union(idx2.difference(idx1))``,
with duplicates dropped.

.. ipython:: python

   idx1 = pd.Index([1, 2, 3, 4])
   idx2 = pd.Index([2, 3, 4, 5])
   idx1.symmetric_difference(idx2)

.. note::

   The resulting index from a set operation will be sorted in ascending order.

When performing :meth:`Index.union` between indexes with different dtypes, the indexes
must be cast to a common dtype. Typically, though not always, this is object dtype. The
exception is when performing a union between integer and float data. In this case, the
integer values are converted to float

.. ipython:: python

   idx1 = pd.Index([0, 1, 2])
   idx2 = pd.Index([0.5, 1.5])
   idx1.union(idx2)

.. _indexing.missing:

Missing values
~~~~~~~~~~~~~~

.. important::

   Even though ``Index`` can hold missing values (``NaN``), it should be avoided
   if you do not want any unexpected results. For example, some operations
   exclude missing values implicitly.

``Index.fillna`` fills missing values with specified scalar value.

.. ipython:: python

   idx1 = pd.Index([1, np.nan, 3, 4])
   idx1
   idx1.fillna(2)

   idx2 = pd.DatetimeIndex([pd.Timestamp('2011-01-01'),
                            pd.NaT,
                            pd.Timestamp('2011-01-03')])
   idx2
   idx2.fillna(pd.Timestamp('2011-01-02'))

Set / reset index
-----------------

Occasionally you will load or create a data set into a DataFrame and want to
add an index after you've already done so. There are a couple of different
ways.

.. _indexing.set_index:

Set an index
~~~~~~~~~~~~

DataFrame has a :meth:`~DataFrame.set_index` method which takes a column name
(for a regular ``Index``) or a list of column names (for a ``MultiIndex``).
To create a new, re-indexed DataFrame:

.. ipython:: python

   data = pd.DataFrame({'a': ['bar', 'bar', 'foo', 'foo'],
                        'b': ['one', 'two', 'one', 'two'],
                        'c': ['z', 'y', 'x', 'w'],
                        'd': [1., 2., 3, 4]})
   data
   indexed1 = data.set_index('c')
   indexed1
   indexed2 = data.set_index(['a', 'b'])
   indexed2

The ``append`` keyword option allow you to keep the existing index and append
the given columns to a MultiIndex:

.. ipython:: python

   frame = data.set_index('c', drop=False)
   frame = frame.set_index(['a', 'b'], append=True)
   frame

Other options in ``set_index`` allow you not drop the index columns.

.. ipython:: python

   data.set_index('c', drop=False)

Reset the index
~~~~~~~~~~~~~~~

As a convenience, there is a new function on DataFrame called
:meth:`~DataFrame.reset_index` which transfers the index values into the
DataFrame's columns and sets a simple integer index.
This is the inverse operation of :meth:`~DataFrame.set_index`.


.. ipython:: python

   data
   data.reset_index()

The output is more similar to a SQL table or a record array. The names for the
columns derived from the index are the ones stored in the ``names`` attribute.

You can use the ``level`` keyword to remove only a portion of the index:

.. ipython:: python

   frame
   frame.reset_index(level=1)


``reset_index`` takes an optional parameter ``drop`` which if true simply
discards the index, instead of putting index values in the DataFrame's columns.

Adding an ad hoc index
~~~~~~~~~~~~~~~~~~~~~~

You can assign a custom index to the ``index`` attribute:

.. ipython:: python

   df_idx = pd.DataFrame(range(4))
   df_idx.index = pd.Index([10, 20, 30, 40], name="a")
   df_idx

Why does assignment fail when using chained indexing?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

:ref:`Copy-on-Write <copy_on_write>` is the new default with pandas 3.0.
This means that chained indexing will never work.
See :ref:`this section <copy_on_write_chained_assignment>`
for more context.

.. _indexing.series_assignment:

Series Assignment and Index Alignment
-------------------------------------

When assigning a Series to a DataFrame column, pandas performs automatic alignment
based on index labels. This is a fundamental behavior that can be surprising to
new users who might expect positional assignment.

Key Points:
~~~~~~~~~~~

* Series values are matched to DataFrame rows by index label
* Position/order in the Series doesn't matter
* Missing index labels result in NaN values
* This behavior is consistent across df[col] = series and df.loc[:, col] = series

Examples:
.. ipython:: python

   import pandas as pd

   # Create a DataFrame
   df = pd.DataFrame({'values': [1, 2, 3]}, index=['x', 'y', 'z'])

   # Series with matching indices (different order)
   s1 = pd.Series([10, 20, 30], index=['z', 'x', 'y'])
   df['aligned'] = s1  # Aligns by index, not position
   print(df)

   # Series with partial index match
   s2 = pd.Series([100, 200], index=['x', 'z'])
   df['partial'] = s2  # Missing 'y' gets NaN
   print(df)

   # Series with non-matching indices
   s3 = pd.Series([1000, 2000], index=['a', 'b'])
   df['nomatch'] = s3  # All values become NaN
   print(df)


   #Avoiding Confusion:
   #If you want positional assignment instead of index alignment:
   # reset the Series index to match DataFrame index
   df['s1_values'] = s1.reindex(df.index)
